What is the mass of of oxygen required for production of 0.72 g of water
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32 gram oxygen is required for production of 36 gram water.
So 0.72 gram water can be produced by- 32/36×0.72=0.64 gram oxygen.
Thanks.
Tripathy.
So 0.72 gram water can be produced by- 32/36×0.72=0.64 gram oxygen.
Thanks.
Tripathy.
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