Question

What is the mass of precipitate formed when 50ml of 16.9 % solution of AgNo3 is mixed with 50ml of 5.8 % NaCl solution ? ( Ag = 107.8 , N = 14 , O = 16 , Na = 23 , Cl = 35.5 )

Answer 1

Heya!!!

Answer to your question:

⚫Moles of AgNo3= 50*16.9/100*169.8

                           = 0.05mol

⚫Moles of NaCl = 50*5.8/100*58.5

                       =0.05mol

Considering the reaction,

AgNo3 + NaCl➡AgCl + NaNo3

mass of AgCl = mole*molar mass

                       =0.05 *143.5

                       = 7.16 g✔

Hope it helps ^_^