Question

what is the mass of sodium hydroxide present in 500ml of 1M NaOH solution
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Answer 1

Needed:  500mL solution with a final concentration of .1M

 

Na:  22.989 AMU

O:   15.999 AMU

H:   1.008 AMU

=39.996 AMU  (rounded to 40amu)

40 amu= 1 mole NaOH

 

To make one mole NaOH solution, dissolve 40 grams NaOH in 500mL of H2O.

 

mL to L conversion:

500/1000=.5

For .5L of 0.1M solution, we need 0.1M of solute.

0.1M of solute x 40 grams/Mole= 4 grams NaOH

Answer 2

Answer:-

Molarity=no of moles / volume in litre

500 ml = 0.5 L

Then you need the no . Of moles

No . Of moles = 0.1 × 0.5 = 0.05 mol

You need 0.05 mol of Naoh to make this solution

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