What is the mass of sodium hydroxide present in 500ml of 1m naoh solution?
Answers
Molar conductivity of a solution at a given concentration is the conductance of volume V of a solution containing 1 mole of the electrolyte kept between two electrodes with the area of cross-sectionAand distance of unit length. If temp. Increases , k of electrolyte Sol. Increases because mobility of ions increases.
Answer:
The mass of sodium hydroxide present in 500 ml of 1M NaOH solution is 20 grams.
Explanation:
What is molarity?
- Molarity (M) = mass of solute (in grams) / molar mass of solute * volume of solution (in liters)
- It is defined as the number of moles of solute per liters of solution.
- Where, moles of solute = mass of solute / molar mass of solute.
For sodium hydroxide (NaOH):
The molecular mass of NaOH = the atomic mass of sodium + the atomic mass of oxygen + the atomic mass of hydrogen
= Na (1) + O (1) + H (1)
= 23 + 16 + 1
= 40 u
Here, the volume of the solution is 500 ml = 0.5 liters, and the molarity is 1.
So,
Molarity = mass of solute (in grams) / molar mass of solute * volume of solution (in liters)
∴ 1 = mass of solute (in grams) / 40 * 0.5
∴ mass of solute (in grams) = 1 * 40 * 0.5
∴ mass of solute = 20 grams
So, the mass of NaOH is 20 grams.
To learn more about the difference between molarity and molality,
https://brainly.in/question/396768
To learn more about the normality,
https://brainly.in/question/12878958
#SPJ3