Question

what is the mass of the body if the acceleration at that place is 1/2 of its value on the surface​

Answer 1

Answer:

We have,

g=

R

2

GM

for mass;

g

′

=

(

2

R

)

2

G(

10

M

)

=

10R

2

GM×4

=

5

2

g

=4m/s

2

∴g

′

=4m/s

2

Explanation:

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Answer 2

Answer:

Let the radius of earth from surface of earth is R and the height equal to half the radius of earth from surface of earth is h.

The acceleration on the surface of earth due to gravity is given as,

g=

R

2

GM

The acceleration at a height due to gravity is given as,

g

′

=

h

2

GM

=

(

2

R

)

2

GM

=4g

=4×10

=40m/s

2

Thus, the value of acceleration at a height due to gravity is 40m/s 2.