Question

What is the mass of two identical objects which experience a force of 6.67×10¹¹N and are separated by a distance of 1m ?​

Answer 1

Explanation:

Let-

The two identical objects have mass m1 and m2.

Then-

Mass of m1 =mass of m2 = m kg

Amount of force (F) = 6.67 × 10¹¹N

Distance between the two objects = 1 meter

By using the formula of Gravitation,

$F \: = G \: \frac{m1m2}{ {r}^{2} }$

The value of G is 6.67×10^-11Nm²/kg².

Therefore-

$6.67 \times {10}^{11} n = \frac{6.67 \times {10}^{ - 11} {m}^{2} }{ {1}^{2} }$

$\frac{6.67 \times {10}^{11} \times 1}{6.67 \times {10}^{ - 11} } {kg}^{2} = {m}^{2}$

${10}^{22} {kg}^{2} = {m}^{2}$

$\sqrt{ {10}^{22} }kg = m$

${10}^{11} kg = m1 = m2$

Hence-

The mass of each identical object is 10¹¹kg.

Answer 2

Answer: UR REQUIRED ANSWER DHONI ;-

LET , the two identical objects  have mass M1 AND M2

then ,

the mass of m1 = mass of m2 = m kg

distance between the objects = 1 m

force = 6.67 × 10 to the power 11  NEWTON

- formula of gravitation

F = G × m1 ×m2 / r²

the value of G Is 6.67×10∧-11Nm²/ kg².

therefore ,

6.67 ×10 ¹¹ n  = 6.67 ×10⁻¹¹ m²

m² = 6.67 ×10 ¹¹ × 1 / 6.67 × 10⁻¹¹ KG²

m²= 10²²kg²

m= √10²²kg

m1 = m2 = 10¹¹ kg

HENCE ,

THE MASS OF EACH IDENTICAL OBJECT IS 10¹¹kg .

Explanation: hope this will help u dhoni , need feedback plz .

itz akansha ,

the dynamite.