what is the mass percentage of oxygen in ethanol 19
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Answer:
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Explanation:
The percentage of Oxygen is: 16.0 g/mol ÷ 46.0 g/mol × 100 = 34.8 % of Oxygen
Answered by
1
Answer:
The percentage of Oxygen is: 16.0 g/mol ÷ 46.0 g/mol × 100 = 34.8 % of Oxygen.
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