Question

What is the mass pf a crate with a net force of 300N and accelerate it by 0.750 m/s2?

Answer 1

Answer:

here formula used is F=ma

Explanation:

F=300,

M=m

A=0.750

apply the above equation

then,

300=0.750m

300/0.750=m

hence mass of the air craft is

m=400

Answer 2

Answer:

We substitute 300 newton for f and 0.750 meter per second square for a now. After dividing, we get m equals to 400 kilograms.

Explanation:

Step : 1 Given: A crate with a net force of 300 N and accelerated by 0.750 ms⁻².

To find: The mass of the crate.

Force is given by the formula,

  F = m x a

Here, F is the force applied on the crate, m is the mass of the crate and a is the acceleration produced.

On replacing the terms with the values given in the question, the obtained equation is,

$300 N=m\left(0.75 m^{-2}\right)$

On rearranging and solving further, the value of m is found to be,

$m=400 \mathrm{~kg}$

Therefore, the mass of the crate is 400 kg.

Step : 2 For acceleration, an equals 16 newtons, which when divided by 0.40 kg, results in an acceleration value of 40 metres per second square. As a result, the ball's acceleration is 40 metres per second squared. Now, after inserting the numbers, we obtain a to equal 25 newtons, which we divide by 0.4 kilogrammes to obtain 62.5 metres per second, second square rounded to one significant figure. Newton's third rule of motion gives us 60 metres per second squared as our answer to question 4.

Step : 3  The net force in the situation is 12 N, and the object's mass is 6 kg. As a result, the rate of acceleration must be 2 m/s2 (or 12 n/kg). Additionally, the acceleration is moving in the same direction as the force being applied.

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