Question

What is the maximum amount of work that can be done in 15 seconds by an engine working at 30 kw

Answer 1

Power = Work done/ Time taken

30000 = W/15

30000 x 15 = W

W = 450000 J

Work done = 450000 Joule = 450 kJ.

Answer 2

GiveN :

• Power (P) = 30 kW
• Time interval (t) = 15 s

To FinD :

• Maximum Work Done

SolutioN :

Convert Power into Watt by multiplying it with 1000

$\implies \rm{Power \: = \: 30 \: kW} \\ \\ \\ \implies \rm{Power \: = \: 30 \: \times \: 1000 \: W} \\ \\ \\ \large \implies {\boxed{\rm{Power \: = \: 30000 \: W}}}$

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Use Formula for Power :

$\large{\boxed{\sf{Power = \dfrac{Work\ Done}{Time\ Taken}}}} \\ \\ \\ \implies \rm{P = \dfrac{W}{t}} \\ \\ \\ \implies \rm{W = P \times t} \\ \\ \\ \implies \rm{W = 30000 \times 15} \\ \\ \\ \implies \rm{W \: = \: 450000 \: J} \\ \\ \\ \implies \rm{W \: = \: \dfrac{450000}{1000} \: kJ} \\ \\ \\ \implies \rm{W \: = \: 450 \: kJ} \\ \\ \\ \underline{\rm{\therefore{Work \: done \: is \: 450 \: kilo \: Joules}}}$