Question

What is the maximum and minimum value of 3cosx +4sinx+5

Answer 1

-√a² + b² ≤ a sin A + b cos A ≤ √a² + b²

= - √4² + 3² ≤ 4 sin x + 3 cos x  ≤√4² + 3²

=  - 5 ≤ 4 sin x + 3 cos x ≤ 5
= -5  + 5 ≤ 4 sin x + 3 cos x ≤ 5 + 5
= 0 ≤ 4 sin x + 3 cos x ≤ 10

so the maximum value is 10 and the minimum value is 0.

Answer 2

Answer:

Step-by-step explanation:

How did the 5+5 came I m not understanding