Question

What is the maximum data rate of a channel with a bandwidth of 200 KHz if we use four levels of digital signaling.

Answer 1

Given:

bandwidth = 200 KHz = 200000 Hz.

The maximum data rate can be calculated as

Nmax= 2 × B × nb

         = 2 × 200000 × log24

         = 8 × 108bps

         = 800 Kbps

Answer 2

Given:

The bandwidth of channel = 200 kHz = 200000 Hz

Level of digital signalling used = 4 levels

To find:

The maximum data rate of channel =?

Solution:

• To calculate the maximum data rate of the channel uses the following steps:
• The data rate is the pace at which the information is transmitted through the networks in the form of bits.
• The data rate is also called a bit rate and is calculated from the formula provided below.
• Data rate = 2 × Bandwidth × log₂  Level

=> Data rate = 2 × 200000 Hz × log₂ 4

=> Data rate = 400000 Hz × 2 ( Because log₂ 4 = 2 )

=> Data rate = 800000 bits per second

=> Data rate in kilobytes per second = 800 kbps

Hence, the maximum data rate of the channel with a bandwidth 200kHz is 800 kbps.