What is the maximum horizontal distance that a ball travels when it is thrown obliquely with a
speed of 3.13 m/s reaches a maximum height of 25 m (take g = 9.8 ms)
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Answer:
Explanation:
Use max height formula h=u^2sin^2¢/2g...
.
Find ¢
Then range =u^2sin2¢/g
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