$ What is the maximum number of emission lines when the excited electron of a H atom in n=6 drops to the ground
state?
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Answered by
2
Explanation:
1 rupees = 75 US dollars
Answered by
4
Answer:
15
Explanation:
n2 = 6
n1 = 1
no of emmission lines = (n2-n1)(n2-n1 +1) / 2
(5)(6)/2
15
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