What is the maximum number of emission lines when the excited electron of a h atom in n = 6 drops to the ground state? 2.16 (i) the energy associated with the first orbit in the hydrogen atom is?
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harshalsarwade2002:
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Answer:
15,2.18 ×10^-18 J,13.6ev
Explanation:
no of emission lines=(n-1) sigma
=(6-1)sigma
=5 sigma
= 5+4+3+2+1=15 lines
2.16(1)
energy of 1 orbit of hydrogen
= -2.18×10^-18 J×(1/n^2)
=-2.18×10^-18×(1/1)
=2.18×10^-18J
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