What is the maximum number of emissions of lines obtained when the excited electron of a hydrogen atom in n = 6th level drop to n = 1st level or ground state ??
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Answered by
4
Number of lines obtained by the excitation of electrons in the hydrogen spectrum is
n (n - 1) / 2
here, n = 6
.: Number of lines obtained
= n ( n - 1 ) / 2
= 6 ( 6 - 1 ) / 2
= ( 6 × 5 ) / 2
= 30 / 2
= 15 //
Total number of lines obtained = 15
n (n - 1) / 2
here, n = 6
.: Number of lines obtained
= n ( n - 1 ) / 2
= 6 ( 6 - 1 ) / 2
= ( 6 × 5 ) / 2
= 30 / 2
= 15 //
Total number of lines obtained = 15
Kimmus:
Thank you :)
Answered by
2
by applying the equation n(n-1)/2
we get 30/2= 15
, so the number of emissions of lines obtained is 15
we get 30/2= 15
, so the number of emissions of lines obtained is 15
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