Question

what is the maximum percentage error in the measurement of kinetic energy, if percentage errors in mass and speed are 2% and 3% respectively

Answer 1

Answer:

• Energy due to motion is called as Kinetic energy.

• Kinetic energy is given as :

• KE = ½mv²

Given:

Percentage error :

1) (∆m/m) × 100 = 2%

2) (∆v/v) × 100 = 3%

We need to find the maximum percentage error in the measurement of kinetic energy.

Solution:

=> K.E = ½mv²

=> (∆K.E/K.E) × 100 = (∆m/m) × 100 + 2 × (∆v/v) × 100

=> (∆K.E/K.E) × 100 = 2% + 2 × 3%

=> (∆K.E/K.E) × 100 = 2% + 6%

=> (∆K.E/K.E) × 100 = 8%