what is the mean proportional of (x+y)^2 and (x-y)^2
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0
Answer:
1:2 mught be the answer i m not sure
Answered by
0
Answer:
Mean proportional of A and B is (A∗B)
1
/2
Therefore, here:
[(x+y)/(x−y)]∗[(x+y)(x−y)/(xy)
2
]
1
/2
=(x+y)/xy
Step-by-step explanation:
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