What is the meaning of the formula $f_D = \frac{2v}\lambda$ in the context of the Doppler effect?
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Hey dear here is the answer
There is a misconception regarding the disintegration constant, lambda (λ) which seems wide-Spread among radiologists, radiological residents, and not a few radiation physicists. In most texts the disintegration constant is defined as “the fractional change in number of atoms which occurs in unit time.” This definition is correct only in the limiting case where the unit time interval is infinitely short. In all other cases, lambda may be a fraction or it may be a number greater than one; it is never the fractional change in number of atoms
Hope its help you
There is a misconception regarding the disintegration constant, lambda (λ) which seems wide-Spread among radiologists, radiological residents, and not a few radiation physicists. In most texts the disintegration constant is defined as “the fractional change in number of atoms which occurs in unit time.” This definition is correct only in the limiting case where the unit time interval is infinitely short. In all other cases, lambda may be a fraction or it may be a number greater than one; it is never the fractional change in number of atoms
Hope its help you
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Heya mate
The answer is here
The formula is
Fd =2v/ λ
♢ The meaning of the formula is that the The Doppler effect refers to change in the observed frequency of a wave if the observer and source are in relative motion.
hope it helps
The answer is here
The formula is
Fd =2v/ λ
♢ The meaning of the formula is that the The Doppler effect refers to change in the observed frequency of a wave if the observer and source are in relative motion.
hope it helps
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