what is the method to do
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we know that
tan c = perpendicular/base
so here AB = perpendicular and BC = base for angle c
tan c = AB/BC
tan c = 6/8
tan c = 3/4
tan c = perpendicular/base
so here AB = perpendicular and BC = base for angle c
tan c = AB/BC
tan c = 6/8
tan c = 3/4
umar61:
i know this but i want answer
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0
It is given in the image that in a right angled trianlge, the hypotenuse is 10cm, it's base is 8cm and height's 6cm.
We need to find tanC.
We know that tanθ = opposite side/adjacent side
Here we need to find angle C.
tanC = AB/BC
= 6/8
= 3/4
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