Question

what is the mid point of a line with endpoint (-3,4) and ( 10,-5) ?

Answer 1

Step-by-step explanation:

apply mid point theorm that is (X1+X2)/2=x

(Y1+Y2)/2=y

here,X1=-3,X2=10,Y1=4,Y2=-5

x and y is mid point

Answer 2

Answer:

$\Large\boxed{\longrightarrow \mathsf{(\frac{7}{2}, -\frac{1}{2})  }}$

Step-by-step explanation:

$\Large\boxed{\mathsf{SUBJECT: MATH}}$

$\Large\boxed{\mathsf{LESSON: MIDPOINT \quad AND \quad SLOPE}}$

To solve this problem, first you have to use the slope formula by using with midpoint formula.

SOLUTIONS:

First, use slope formula.

$\Large\boxed{\mathsf{SLOPE \quad FORMULA}}$

$\displaystyle \mathsf{\frac{Y_2-Y_1}{X_2-X_1}}}$

You can also use midpoint formula.

$\displaystyle \mathsf{\frac{Y_1,X_1}{Y_2,X_1}}$

$\displaystyle \mathsf{=\frac{X_2+X_1}{2}, \frac{Y_2+Y_1}{2}   }}}}$

$\displaystyle \mathsf{Y_2=(-5)\\}}\\\\\displaystyle \mathsf{Y_1=4}\\\\\displaystyle \mathsf{X_2=10}\\\\\displaystyle \mathsf{X_1=(-3)}$

Solve.

$\displaystyle \mathsf{\frac{10-3}2,\frac{-5+4}{2} }}}$

Subtract numerators from left to right numbers.

$\Rightarrow \displaystyle \mathsf{10-3=7, \quad -5+4=-1}$

Refine the problem down.

$\displaystyle \mathsf{\left(\frac{7}{2}, -\frac{1}{2}\right)  }$

$\longrightarrow \displaystyle \Large\boxed{\mathsf{\left(\frac{7}{2}, -\frac{1}{2}\right)}}}}}$

The midpoint of a line of (-3, 4) and (10, -5) is (7/2, -1/2).