Question

what is the minimum electrical force between two charged particle 1 m apart in free space

Answer 1

Answer:

2.404×10^-28

Explanation:

F=k qq/r^2

F= 9×10^9 × 1.602×10^-19 × 1.602×10^-19/ 1

F= 2.304×10^-28

Answer 2

Given:

Two charges are separated by a distance of 1m.

To Find:

The minimum electrical force between the particles.

Solution:

From Coulomb's law, we know that the magnitude of the electrical force between two charges $q_1$ and $q_2$ separated by a distance $r$ is given by

                                $F=k\frac{q_1q_2}{r^2}$

where $k=9*10^9Nm^2/C^2$ is the Coulomb's law constant.

Now the force will be minimum when the charges are minimum and since charges are quantized, the minimum values of the two charges are $e=1.6*10^{-19}C$.

                               $F=k\frac{(e)(e)}{1^2}$

                          ⇒ $F=ke^2=2.3*10^{-28}N$

Hence, the minimum electrical force between the charges is $F=2.3*10^{-28}N$.