Question

What is the minimum number of bits required to represent at least 3 different values?

Answer 1

Step-by-step explanation:

If you want to represent one character from the 26-letter Roman alphabet (A-Z), then you need log2(26) = 4.7 bits. Obviously, in practice, you'll need 5 bits

Answer 2

Answer:

Minimum number of bits required to store any 3 digit decimal number is 10.

Step-by-step explanation:

• To calculate the number of possibilities given the number of digits: possibilities = baseⁿdigits.
• So if you have 3 digits in decimal ( base 10) you have 10³=1000 possibilities.
• Then you have to find a number of digits in binary ( bits, base 2 ) so that the number of possibilities is at least 1000, which in this case is 2¹⁰=1024 ( 9 digits is not enough because 2⁹=512 which is les  than 1000).
• If you generalize this, you have 2ⁿbits=possibilities<=> n bit=log₂(possibilities).
• Which applied gives: log₂(1000)=9.97 and since the number of bits has to be an integer, you have to round it up to 10.

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