Math, asked by sonu2034, 9 months ago

What is the minimum to be subtracted from the number 8983 so that in the given number, dividing by 10 15, 16,20 or 32, there is 7 left in each case?​

Answers

Answered by nalanagulajagadeesh
0

Answer:

336

Step-by-step explanation:

given number should be divided by 10,15,16,20&32 and leave remainder 7,

LCM of 10,15,16,20&32 is 480,

that means when 8983 is divided by 480,we get 343 as remainder,

so ,if we subtract 343 from 8983,we get 8640 which is exactly divisible by 480,but also given that we should get remainder as 7 when divided by 10,15,16,20&32.

therefore that number is 8647,

and the minimum number to be subtracted from 8983 which is divided by 10,15,16,20&32 by leaving remainder 7 is 8983-8647=336.

Hope it helps u...

Answered by Anonymous
0

Answer:

here is the ans mate hope this is helpful to you

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