What is the minimum value of abs(286m-351n-617) as m,n take all integer values?
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3
Given, abs(286m - 351n - 617) where abs denotes absolute value.
first of all we have to eliminate the common number from each term. here we see 13 is common in all both variable terms so, eliminate it ,
e.g., P(m, n) = 13(22m - 27n) - 617
P(m, n) = 13x - 617 [ assume (22m - 27n) = x ]
now, Let's take a number x in such a way that 13x will be closest from 617 .
take x = 48 then, 13x = 624 - 617 = 7
hence, minimum value of abs(286 - 351n - 617) = 7 for all integers value of m , n
first of all we have to eliminate the common number from each term. here we see 13 is common in all both variable terms so, eliminate it ,
e.g., P(m, n) = 13(22m - 27n) - 617
P(m, n) = 13x - 617 [ assume (22m - 27n) = x ]
now, Let's take a number x in such a way that 13x will be closest from 617 .
take x = 48 then, 13x = 624 - 617 = 7
hence, minimum value of abs(286 - 351n - 617) = 7 for all integers value of m , n
Answered by
1
Answer:
Step-by-step explanation:
abs(286m-351n-617)
=abs(13(22m-27n)-617)
let 22m-27n=x
therefore
abs(286m-351n-617)
=abs(13x-617)
we know that 13*47=611
so,abs(611-617)=abs(-6)=6
because,Absolute value describes the distance of a number on the number line from 0 without considering which direction from zero the number lies. The absolute value of a number is never negative.
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