What is the missing number 1,3,10,21,64,129 ? 777
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Answer:
388
Step-by-step explanation:
n1 = 1
n2 = 3
n3 = 10
n4 = 21
n5 = 64
n6 = 129
n7 = ?
n8 = 777
It follows the pattern,
(2n + 1), (3n + 1), (2n + 1), (3n + 1), and so on..
where, n is the previous number
n1 = 1
n2 = 2(n1) + 1 = 3
n3 = 3(n2) + 1 = 10
n4 = 2(n3) + 1 = 21
n5 = 3(n4) + 1 = 64
n6 = 2(n5) + 1 = 129
n7 = 3(n6) + 1 = 388
n8 = 2(n7) + 1 = 777
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