Question

what is the molality of a solution of 69 grams of NaOH and 2000grams of H2O?​

Answer 1

Answer:

0.83m

Explanation:

No.of moles of NaOH = 69g/40g/mol

= 1.725mol

molarity =(1.725/2069)×1000m = 0.83m

Answer 2

Answer:-

0.8625 m

Explanation:-

• Molar mass of Na (Sodium) = 23g

• Molar mass of O (Oxygen) = 16g

• Molar mass of H (Hydrogen) = 1g

Hence, molar mass of NaOH:-

= 23+16+1

= 40g

In this solution, NaOH is solute and H₂O is solvent.

Number of moles in 69g of NaOH :-

= Given Mass/Molar mass

= 69/40

= 1.725 moles

Now, let's convert the mass of H₂O

from g to kg.

=> 1g = 0.001kg

=> 2000g = 2000(0.001)

=> 2kg

Molality of a solution

= Moles of solute/Mass of solvent in kg

= 1.725/2

= 0.8625 m

Thus, molality of the solution is

0.8625 m.