What is the molality of the solution of methanal in water in which the mole fraction of methanal is 0.25
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Methanol mol fraction = 1-0.25 = 0.75
Mass of water, in grams: = 0.25(18 g/mol) = 4.5 g
Mass of methanol, in grams = 0.75(32.04 g/mole) = 24.03 g
Total mass = 4.5 + 24.03 = 28.53 g = 0.02853 kg
Molality = moles solute / kg solution
m = 0.25 / 0.02853
m = 8.76 moles / kg <~~Answer
Mass of water, in grams: = 0.25(18 g/mol) = 4.5 g
Mass of methanol, in grams = 0.75(32.04 g/mole) = 24.03 g
Total mass = 4.5 + 24.03 = 28.53 g = 0.02853 kg
Molality = moles solute / kg solution
m = 0.25 / 0.02853
m = 8.76 moles / kg <~~Answer
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