What is the molar kinetic energy of nitrogen gas at 25˚c?
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Kinetic energy = 1.5kT
= 1.5 * 1.38*10^-23 * (273 + 25)
= 6.168 * 10^-21 J
Kinetic energy of nitrogen gas is 6.168 * 10^-21 J
= 1.5 * 1.38*10^-23 * (273 + 25)
= 6.168 * 10^-21 J
Kinetic energy of nitrogen gas is 6.168 * 10^-21 J
Answered by
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Given,
Temperature(T) = 25°C
We know,
K.E = 1.5kT
K.E = 1.5 × 1.38 × 10^-23 × {273 + 25}
K.E = 6.168 × 10^-21 J
Temperature(T) = 25°C
We know,
K.E = 1.5kT
K.E = 1.5 × 1.38 × 10^-23 × {273 + 25}
K.E = 6.168 × 10^-21 J
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