Question

What is the molarity of 0.25mol of Nacl in 300ml of solution?

Answer 1

Molarity = ?

no. of moles of NaOH used = 0.25 moles.

Volume of solution = 300 mL or 0.3 L

Molarity = (moles of solute)/(liters of solution)

=> 0.25/0.3

=> 2.5/3

=>0.833 M

Hence, the molarity is 0.833 M (molar or M L-1)