Question

What is the molarity of 2.34 mol of calcium carbonate in 1860 mL of solution?

Answer 1

Answer:

Molarity=Moles of solute/volume of solution in litre

here, moles =2.34

volume= 1860ml=1.86lt

Therefore, Molarity=2.34/1.86 = 1.25mol/lt(approx)

Answer 2

Given:

Moles of solute (Calcium carbonate) = 2.34 mol

Volume of solution = 1860ml

To find:

Molarity of the solution = ?

Formula to be used:

Molarity =  $\frac{Number of moles}{Volumes in Litres}$

Calculation:

As the volume is given in ml, it must be converted into L,

∴ 1860 ml = 1.86 L

Thus substituting the given values in the following formula, it gives the molarity of the solution

Molarity = $\frac{Number of moles}{Volumes in Liters}$

Molarity = $\frac{2.34}{1.86}$

Molarity = 1.25

Conclusion:

Thus the molarity of the calcium carbonate solution is calculated as 1.25M.

Learn more about Molarity

The resultant molarity of solution made by mixing 600 ml of 2 M NaOH solution and 400 ml of 3M NaOH solution is

(1) 1 M

(2) 1.2 M

(3)2.4 M

(4) 3.6 M​

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