What is the molarity of 2N aqueous solution of ca (oh) 2?
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Explanation:
02 M
pH+pOH = 14
pOH = 2
pOH =− log[OH
−
]
antilog (-2) = [OH
−
]
= 0.01
1mol Ca(OH)
2
produces 2 mol OH
−
= 2 x 0.01 =0.02
Hence,
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