what is the molarity of molal solution of Nacl with density 1.21g/cm^3
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Answer:
Explanation:
1mole of nacl contains 1000g of water solution
58.5 of nacl contains 1000g of water solution
total mass = 1000+58.5=1058.5
density (d)= mass/ volume ( m/v)
volume= m/d=1058.5/1.21=874.7933
molarity =1/874.7933=0.001143
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