What is the molarity of the resulting solution obtained by mixing 2.5 l of 0.5 m urea solution?
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Answered by
11
The 0.5M and 2M refer to moles per liter (of solution).
Volume of final solution is 2.5 L + 500 mL = 2.5 L + 0.5 L = 3.0 L.
Now
moles in First solution (0.5 mol/L)*(2.5 L) = 1.25 mol
moles in Second solution (2 mol/L)*(0.5 L)= 1 mol
Molarity: (1.25 mole + 1 mole)/(3.0 L) = 0.75 moles/L = 0.75 M
THus the molarity of the resulting solution is 0.75M
hope it helps u
Anita Dahiya answered this
Total volume in the liquid
Total moles of urea in 3 L
= (2 × 0.5) + (0.5 × 2)
= 2.25 moles
Therefore,
Molarity = 2.25 / 3
= 0.75 moles
Volume of final solution is 2.5 L + 500 mL = 2.5 L + 0.5 L = 3.0 L.
Now
moles in First solution (0.5 mol/L)*(2.5 L) = 1.25 mol
moles in Second solution (2 mol/L)*(0.5 L)= 1 mol
Molarity: (1.25 mole + 1 mole)/(3.0 L) = 0.75 moles/L = 0.75 M
THus the molarity of the resulting solution is 0.75M
hope it helps u
Anita Dahiya answered this
Total volume in the liquid
Total moles of urea in 3 L
= (2 × 0.5) + (0.5 × 2)
= 2.25 moles
Therefore,
Molarity = 2.25 / 3
= 0.75 moles
Answered by
9
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