What is the molecular formula of a compound containing only carbon and hy drogen if combustion of 1.05g of the compound produces 3.30g CO₂ and 1.35g H₂O and its molar mass is about 70g?
Answers
Answer:
A compound containing only carbon and hydrogen produces 3.30g CO₂ and 1.35g H₂O on combustion of 1.05g and has a molar mass of 70g. Then its molecular formula is C₅H₁₀.
Explanation:
Given that,
mass of compound = 1.05g
molar mass of compound = 70g
mass of CO₂ = 3.30g
mass of H₂O = 1.35g
we know that,
number of moles = mass / molar mass
then,
moles of CO₂ = 3.3 / 44 = 0.075 mol.
ie, it contains 0.075 moles of C.
moles of H₂O = 1.35g / 18gmol⁻¹ = 0.075 mol.
ie, it contains 2×0.075 moles of H.
then, ratio C : H = 0.075 : 0.15
⇒ = 0.075/0.075 : 0.15/0.075
⇒ = 1 : 2
Empirical formula is CH₂
Empirical formula mass = 14g
Molecular Formula= n × Empirical formula
n = molar mass / empirical formula mass
⇒ = 70g / 14g = 5
then, molecular formula = C₅H₁₀
Answer:
C5H10
Explanation: