Question

what is the molecular formula of the alkane, the 5.6 litre of which weight 11 g at STP

Answer 1

The correct answer is propane C3H8 .If we divide the given volume by 22.4 it will give the number of moles that is 0.25. Then divide given mass by 0.25 the mola mass of the alkane will be obtained that is 44 gram.

Answer 2

at stp any gas occupies 22.4 L of volume for each mole.So you have 0.25 moles. if it weighs 11g then 1 mole weighs 44 g.

alkane with 44g of mass is C3H8


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