Question

what is the multiplying factor as we go to the right of the decimal in the place value table ?​

Answer 1

Answer:

Step-by-step explanation:

Let the tense digit be x

And the units digit be y

The original equation is 10x+y

Acc. to first statement

10x+y=(x+y)×8+1

10x+y=8x+8y+1

10x-8x=8y-y+1

2x=7y+1......(i)

Acc to the second statement

10x+y=(x-y) ×13+2

10x+y=13x-13y+2

10x-13x=-y-13y+2

-3x=-14y+2

-3x+14y=2.....(ii)

Multiply equ I by 2 and add it with equ ii

4x-14y=2

-3x+14y=2

________

X=4

Now substitute the value of x in equ i

2(4)-7y=1

8-7y=1

8-1=7y

7=7y

Y=1

The original two digit no. =10x+y

=10(4)+1

=40+1=41

Step-by-step explanation: