Question

What is the n factor or valency factor of sodium oxalate Na2C2O4?​

Answer 1

Answer:

Valency of each sodium ion is 1 and oxidation state +1.Valency of oxalate ion is 2 and oxidation state -2.

Explanation:

Answer 2

Answer:

What is the n factor or valency factor of sodium oxalate Na2C2O4?​

Explanation:

The valency of each sodium ion is 1 and the oxidation state is +1. Valency of oxalate ion is 2 and oxidation state -2.

What is Valency?

Valency is the combining power of an element. Elements in the same group of the periodic table have the same valency. The valency of an element is related to how many electrons are in the outer shell.

How to Calculate Valency?

If the outermost shell of an atom contains 4 or less than 4 electrons, then the valency of an element is equal to the number of electrons present in the outermost shell and if it is greater than 4, then the valency of an element is determined by subtracting the total number of electrons ...

Formula to Calculate Valency?

The valency of Na is 1

The valency of C is 2

The valency of O is 4

So,

Na2C2O4= (1×2)+(2×2)+(4×4)

                 = 2 + 4 +16

                  =32

The Hybridisation of this outermost shell is 4p2.

Hence n=2

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