Question

what is the nature of the roots of the quadratic equation 4x square minus 12x +9=0

hi my dear friends please answer this question​

Answer 1

Answer:

Real and Equal roots

Step-by-step explanation:

Given Quadratic Equation is 4x² - 12x + 9 = 0.

On comparing with ax² + bx + c = 0, we get

a = 4, b = -12, c = 9.

We know that,

D = b² - 4ac

  = (-12)² - 4(4)(9)

  = 144 - 144

  = 0

Since D = 0

Hence, the equation has real and equal roots.

Hope it helps!

Answer 2

$4 {x}^{2} - 12 + 9 = 0 \\ \\ 4 {x}^{2} - 6x - 6x + 9 = 0 \\ \\ 2x(2x - 3) - 3(2x - 3) = 0 \\ \\ (2x - 3) \: (2x - 3) = 0 \\ \\ 2x - 3 = 0 \\ \\ 2x = 3 \\ \\ x = \frac{3}{2} \\ \\ 2x - 3 = 0 \\ \\ 2x = 3 \\ \\ x = \frac{3}{2}$

it has equal and real roots

hope it helps you!
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