Question

What is the net ionic equation of the reaction of FeCl2 with NaOH? Express you answer as a chemical equation including phases.

Answer 1

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Answer 2

Explanation:

The net ionic equation of the reaction of $FeCl_{2}$ with NaOH is as follows.

      $FeCl_{2}(s) + NaOH(l) \rightarrow Fe(OH)_{2}(aq) + NaCl(s)$

To balance the equation, number of reactants should be equal to the number of products.

Number of reactant molecules are as follows.

• Fe = 1
• Cl = 2
• Na = 1
• OH = 1

Number of product molecules are as follows.

• Fe = 1
• Cl = 1
• Na = 1
• OH = 2

Since, number of Cl atoms on reactant side equals 2 therefore, multiply NaCl by 2. Also, number of OH atoms on product side are 2 therfore, multiply NaOH by 2.

Hence, the equation will be as follows.

    $FeCl_{2}(s) + 2NaOH(l) \rightarrow Fe(OH)_{2}(aq) + 2NaCl(s)$