What is the no . Of atoms in 5.3gram of sodium carbonate where atomic mass is 106gram
Answers
Answered by
0
no. of molecules in 5.3 g of Na2CO3
=5.3 *6.022*10²³ /106
= 120.44* 10²³
no. of atoms. = 6*120.44*10²³
= 722.64*10²³
=5.3 *6.022*10²³ /106
= 120.44* 10²³
no. of atoms. = 6*120.44*10²³
= 722.64*10²³
Similar questions
Social Sciences,
7 months ago
India Languages,
7 months ago
Math,
7 months ago
Social Sciences,
1 year ago
Physics,
1 year ago
Chemistry,
1 year ago