What is the no . Of atoms in 5.3gram of sodium carbonate where atomic mass is 106gram
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no. of molecules in 5.3 g of Na2CO3
=5.3 *6.022*10²³ /106
= 120.44* 10²³
no. of atoms. = 6*120.44*10²³
= 722.64*10²³
=5.3 *6.022*10²³ /106
= 120.44* 10²³
no. of atoms. = 6*120.44*10²³
= 722.64*10²³
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