Question

What is the nth in the arithmetic sequence: 0.2,- 0.6,- 1.4,- 2.2?

Answer 1

Solution:

Given Arithmetic sequence : 0.2,-0.6,-1.4,-2.2

first term (a) = 0.2

common difference (d)

= a2 - a1

= -0.6 - 0.2

= -0.8

$\boxed {n^{th} term = a_{n}=a+(n-1)d}$

= 0.2 + (n-1)(-0.8)

= 0.2 -0.8n+0.8

= 1+0.8n

Therefore,

$n^{th} term = a_{n}=1+0.8n$

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