What is the number of atoms in 8.5 g of NH3?
Answers
Answered by
75
8.5/17 = 0.5
0.5 moles of NH3 are present.
0.5×6.022×10^23 = 3.011×10^23 molecules of NH3. Each NH3 molecule has 4 atoms. Therefore total number of atoms are 3.011×10^23 × 4 =12.044×10^23 atoms.
0.5 moles of NH3 are present.
0.5×6.022×10^23 = 3.011×10^23 molecules of NH3. Each NH3 molecule has 4 atoms. Therefore total number of atoms are 3.011×10^23 × 4 =12.044×10^23 atoms.
gogoiabhilakh:
But op gupta s chemical engineering books says its 9.03
no then its wrong
send me the pic of question if you have it.
if the answer is clear to u then please mark this as brainliest
Answered by
8
Given:
Mass of NH3 = 8.5g
To find:
The Number of atoms in 8.5g of NH3
Solution:
Number of moles = Given mass/Molar mass
Molar mass of NH3 = 14+(3x1) (Nitrogen - 14; Hydroen- 1)
= 17 g
Number of moles = 8.5/17
= 0.5
1 mole of atoms = 6.022 x 10^23
0.5 mole of atoms = 0.5 x 6.022 x 10^23
= 3.011 x 10^23 atoms
Hence, in 8.5g of NH3, there are 3.011 x 10^23 atoms.
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