Question

what is the number of electrons gained at cathode when 1.08 grams of silver is electroplated on a metal tray

Answer 1

The number of electrons gained at the cathode when 1.08 grams of silver is electroplated on a metal tray is 6.022 × 10^21 electrons.

Given:

1.08 grams of silver.

To Find:

The number of electrons gained at the cathode when 1.08 grams of silver is electroplated on a metal tray.

Solution:

To find the number of electrons gained at the cathode when 1.08 grams of silver is electroplated on a metal tray we will follow the following steps:

As we know,

The cathode is the electrode in which reduction or electrons are gained and a decrease in oxidation number takes place.

Silver is electroplated on the cathode so, the reaction taking place here is:

${Ag}^{ + } + 1 {e}^{ - 1} = Ag$

Also,

The molecular mass of silver = 108g

It means 108 grams of silver deposited by 1 mole or Avogadro number of electrons.

So,

1 gram of silver deposited by

$= \frac{6.022 \times {10}^{23} }{108} electrons$

1.08 grams of silver deposited by

$= \frac{6.022 \times {10}^{23} }{108} \times 1.08 \: = 6.022 \times {10}^{21} \: electrons$

Henceforth, the number of electrons gained at the cathode when 1.08 grams of silver is electroplated on a metal tray is 6.022 × 10^21 electrons.

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