Question

What is the number of electrons that would weigh 1×10^-6 gram.(given mass of electron=9.11×10^-31 kg)

Answer 1

Answer: Given : mass of an electron=9.11 x 10⁻³¹kg =9.11 x 10⁻²⁸g 1kg=1000g Number of electrons present in 1kg will be : =1000/9.11 x 10⁻²⁸ =109.76 x 10 ²⁸ ∴ Number of electrons present in 1kg would be 109.

Answer 2

Answer:109.76X10^28

Explanation:

Given : mass of an electron=9.11 x 10⁻³¹kg =9.11 x 10⁻²⁸g 1kg=1000g Number of electrons present in 1kg will be : =1000/9.11 x 10⁻²⁸ =109.76 x 10 ²⁸ ∴ Number of electrons present in 1kg would be 109.76X10^28