What is the number of nitrogen atoms in 66 g of (NH4)2SO4? [Avogadro's constant= 6.02 x 10^23 mol-1 ; Molar mass of (NH4)2SO4 = 132 g mol-1]
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(NH4)2SO4 = 36 + 32 + 64 =132
no. of moles = wt/mol.wt = 66/132 = 0.5
1 molecule contains 2 atoms of nitrogen.
no. of atomic moles of nitrogen = 2 x 0.5 = 1 mole.
we know that 1 mole contains 6.023 x 10^23 no.of atoms of N
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