Question

What is the number of positive integers that divide 1 2 3 4 5 6 7 8 9 10 without leaving a remainder

Answer 1

Answer:

1 is that number by which no remainder left.

Answer 2

Answer:

The number $1$ is the only positive integer that divide $1,2,3,4,5,6,7,8,9,10$ without leaving remainder.

Step-by-step explanation:

Using division algorithm,

$a=bq+r$, where $a$ is dividend, $b$ is divisor, $q$ is quotient and $r$ is remainder.

For dividend, $a=1$.

$1=1.1+0$, remainder is $0$.

For dividend, $a=2$.

$2=1.2+0$, remainder is $0$.

For dividend, $a=3$.

$3=1.3+0$, remainder is $0$.

For dividend, $a=4$.

$4=1.4+0$, remainder is $0$.

For dividend, $a=5$.

$5=1.5+0$, remainder is $0$.

For dividend, $a=6$.

$6=1.6+0$, remainder is $0$.

For dividend, $a=7$.

$7=1.7+0$, remainder is $0$.

For dividend, $a=8$.

$8=1.8+0$, remainder is $0$.

For dividend, $a=9$.

$9=1.9+0$, remainder is $0$.

For dividend, $a=10$.

$10=1.10+0$, remainder is $0$.

Therefore, 1 is the positive integer that divide $1,2,3,4,5,6,7,8,9,10$ without leaving remainder.

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