Question

What is the number of two digit numbers
excluding 27, which when reversed
results in a number which is greater than
the original number by 45?​

Answer 1

Answer:

16

Step-by-step explanation:

16+45=61

you have to solve it by simple trial and error method

Answer 2

$10x+y+27=10y+x \\ </p><p>10x-x+y-y+27=10y-y+x-x \\ </p><p>(9x+27)/9=9y/9 \\ </p><p>y=x+3 \\ \\ </p><p></p><p>10x+y+27=10y+x \\ </p><p>10x+x+3+27=10(x+3)+x \\ </p><p>11x+30=11x+30 \\ \\ </p><p></p><p>If x+y=15 \\ </p><p>x+x+3=15 \\ </p><p>2x+3–3=15–3 \\ </p><p>2x÷2=12÷2 \\ </p><p>x=6 \\ </p><p>6+y=15 \\ </p><p>6–6+y=15–6 \\ </p><p>y=9 \\ </p><p>So 69+27=96 \\ </p><p>$