Question

What is The number of valance electron in a) Sodium ion (NA) ? b) Oxide ions (O2-) [ Atomic no.. of Na = 11 O = 8 ]
please ans..

Answer 1

Your answers are:-
(a) Electronic configuration of Na: 2, 8, 1
so, Electronic configuration of Na+¹ :2, 8
So, 8 is no. of valence electrons.

(b)Electronic configuration of O: 2, 8, 6
so, Electronic configuration of O-² :2, 8, 8
So, 8 is no. of valence electrons.

Answer 2

sodium ion ---> $Na^{+}$

sodium has deficiency of 1 electrons

electronic configuration of $Na^{+}$ is 2,8

valence electron of $Na^{+}$ = 8

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oxide ion -------> $O^{-2}$

oxide ion has 2 electrons extra

electronic configuration of $O^{-2}$ is 2,8

valence electron in $O^{-2}$ ion = 8