Math, asked by rimfun, 1 year ago

what is the number of zeros in 15*32*25*22*40*75*98*112*125

Answers

Answered by Anonymous
6
15*32*25*22*40*75*98*112*125
=(
15*32)*(25*22)*(40)*(75*98)*(112*125)
=480 * 550 * 40 * 7350 * 14000
= 264000 * 40 * 102900000
= 264* 100 * 4 * 10 * 1029 * 100000
= 264*4*1029* 10^8

So total 8 zeroes.
Answered by PinkyTune
6
15*32*25*22*40*75*98*112*125
=(
15*32)*(25*22)*(40)*(75*98)*(112*125)
=480 * 550 * 40 * 7350 * 14000
= 264000 * 40 * 102900000
= 264* 100 * 4 * 10 * 1029 * 100000
= 10866240000000

So therefore, there are 8 zeroes, in the product '10866240000000 '
(if you are not so sure, then count it!)
 
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