Question

What is the % of acetic acid (CH3COOH) present in a 100 ml solution of a 0.01M acetic acid solution? Molar mass of acetic acid is 60.06 g/mole

Answer 1

Explanation:

1000ml 1M (CH3COOH) = 60.06g

100ml 0.01M CH3COOH= (60.06×0.01×100)/1000

= 0.06006 ℅